Sabina, ranked 196 and four inches shorter than her six-foot tall rival who is a former world no. 12 player, won the one hour, 56-minute match 3-6 6-4 6-2 to earn a shot at Slovenia's Dalila Jakupovic in the semi finals of the WTA series event tomorrow.
Jakupovic beat back the challenge of qualifier Alize Zim of France in straight sets, 6-3 6-1 in just under an hour in an earlier quarter final at the Cricket Club of Indias courts.
After winning the second set to restore parity, Sharipova traded breaks with her rival in the first two games of the decider before breaking her rivals serve in the third to go 2-1 up.
The 23-year-old Uzbek player had to save two break-points in the next game to hold her serve for a 3-1 lead and then broke Wickmeyers serve again to take a 5-2 lead.
More From This Section
She held her serve comfortably to come out a deserving winner against the 28-year-old Belgian who was a top-30 player for four years running between 2009 and 2012 and a semi- finalist at the US Open in 2009.
Results:
Singles (Quarter finals): Dalila Jakupovic (SLO) bt Q-Alize Lim (FRA) 6-3 6-1; Sabina Sharipova (UZB) bt 3-Yanina Wickmayer (BEL) 3-6, 6-4, 6-2.
Doubles (quarter-finals): 2-Dalila Jakupovic (SLO)/Irina Khromacheva (RUS) bt Karman Thandi/Pranjala Yadlapalli (IND) 6-4, 6-2; 4-Julia Glushko (ISR)/Priscilla Hon (AUS) bt Junri Namigata (JPN)/Peangtarn Plipuech (THA) 7-6(5), 6-3; Q-Beatrice Gumulya (INA)/Ana Veselinovic (MNE) bt 1-Oksana Kalashnikova (GEO)/Veronika Kudermetova (RUS) 6-0, 6-1;